Monday, February 7, 2011

Math 10 Assignment

Today's assignment:
- Complete Exercises p. 34-35 #4-16, 18, 21

For those who were not here today, read the examples in section 1.4.

8 comments:

  1. Hi Mr.Arocena may I please come in sometime tomorrow to get help with this assignment? Thank-you!

    -Suzanne

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  2. No problem. I will be in my room before and after school and at lunch.

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  3. I'm having problems with finding the surface area of a cone and the height of a pyramid/cone I took the notes but I'm not sure if I'm doing it right anymore. Please and thank you



    -Bryanna

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  4. Remember to use pythagoras' theorem when calculating the height of the pyramid or cone.

    For the pyramid you need to know the base length (for the cone you need to know the radius) and the slant height and it helps if you draw the pyramid (or cone) as seen from the side.

    Also take a look at example 3 on page 32 in your text book. That should help you visualize what I mean by draw the pyramid/cone as seen from the side.

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  5. Question nine is annoying me. I need to figure out the lateral area. Hello, by the way. The slant height is 73ft and the base is 48ft.
    To calculate the height, I have to do such, right? H^2 = 73^2 - (48/2)^2
    If so then the height I got is 68.9
    In order to figure out the lateral area, I believe that LA = 4((48*68.9)/2), which gives me 6614.4. Am I doing something wrong, if you can tell based on the information I gave you? I could just come in at break or lunch tomorrow if you would prefer, as I may being confusing.

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  6. Remember the lateral area for a pyramid is just the (# of triangles) X (area of each triangle)

    The area of each triangle is equivalent to the (base of the pyramid) X (slant height) / 2

    You didn't have to figure out the height of the pyramid (the equation is correct though for calculating the height)

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  7. Remember that slant height and actual height of the pyramid are different.

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