This was Wednesday's assignment:
- Complete Exercises p. 547-548 #1-4
This was yesterday's assignment:
- Complete Exercises p. 558 #1-11, 13
If you guys have any questions about any assignments you are working on over spring break, post it here. Even though it is a holiday, I will still help you guys out if you need it!
Enjoy your Spring Break!
hey could you re explain to me about indrect proofs? i dont get it at all....
ReplyDeleteWhen you do an indirect proof you are trying to prove that the contrapositive of the initial statement is false (if the contrapositive is false, the original statement must be true).
ReplyDeleteCheck out this page it gives you step-by-step instructions on how to do an indirect proof as well as some examples.
http://www.saskschools.ca/curr_content/mathc30/unit6/Lesson6.htm
Hope that helps. If you need any more help don't be afraid to ask again!
okay thanks
ReplyDeleteDo you happen to know any good website that i can print off all, or most of the triangle theorems?
ReplyDeleteTry the Khan Academy (http://www.khanacademy.org/).
ReplyDeleteThey have some good videos in the geometry section (not the videos in the California standards section)
Let me know what theorems you are looking for (there are a lot of triangle theorems) and I'll see if I can locate some good tutorials to help you out.
Okay well this isnt a triangle theory but can you find one for perpendicular lines, and parallel lines? :)
ReplyDeleteHeres the question im on if it helps.
ReplyDeleteUse the diagram... ( the diagram is just a straight horizontal line with a dot marked "P" above it right over the middle of the line.)
prove that only one perpendicular can be drawn from the point P to the line.
Im kinda skipping ahead through the assignments i have left to do and heres a couple more questions.. i just have to leave soon so i wont have the internet anymore.
ReplyDeleteThe information storage pattern on a floppy disk is organized by sector and track.
a) One common format uses 80 tracks and 18 sectors. Explain what this means.
b) draw a diagram to show what the storage pattern would look like on a floppy disk containing 10 tracks and 18 sectors.
For the line question, are there hash marks showing the line is bisected?
ReplyDeleteFor the circle question
Each track is a circle.
Each sector is a section of the circle.
So a disk with 1 track and 18 sectors would be one circle with 18 sections.
For parallel lines a quick search brought this website up:
http://www.mathsisfun.com/geometry/parallel-lines.html
Hope it helps. If you need more help don't be afraid to ask!
hey
ReplyDeletehow do i calculate the perimeter of an inscribed regular polygon in a circle?
diameter is 17 centimeters and the polygon has 6 sides.
plus can a chord also be a diameter? i cant find what pages the defintions where on in our textbook.
If the polygon is a regular polygon of 6 sides you should be able to break up the polygon into 6 different equilateral triangles and the sides of the triangle should be related to the circle.
ReplyDeleteA chord can be a diameter. Remember a diameter is just a line that starts at one point on the circle and ends at another. If the chord goes through the centre it is then a diameter.
i broke it up into equilateral triangles but im not sure where to go from here.... so far ive got one side of a triangle is half of 17..... 8.5
ReplyDeleteshould the triangles i break it down into be right angle traingles, or a bigger isosceles triangle? then how do i find the base... do i use the a squared = b squared + c squared?
oh okay thats what i wrote down for the chord.
Equilateral triangles means what? ;)
ReplyDeleteoh wait a minute..... i accidently put equilateral instead of congruent... sorry.
ReplyDeleteso i have an isosceles triangle with two sides equaling 8.5 ... how do i know if their equalateral or not with just this information? how can i find out the base? grr this question is frustrating me. >:@
the back of the book says the answer is 51 so i guess it means that they are equalateral... but how do i know for next time when i dont have the back of the book?
ReplyDeleteThe problem defines the polygon as a regular polygon. Remember that regular polygons have sides that are all the same (so the six sides of the inscribed polygon are all the same)
ReplyDeleteSo if each congruent triangle has two equal sides and the third side is part of a polygon that has equal sides, that third side should be the same as the two equal sides of the triangle right?
yes but how do i know whether its an equalateral triangle? or will it always be equalateral if its a regular polygon?
ReplyDeletethe next answer in the back of the book says 48 (square root symbol) 2... but its the exact same type of question.... radius is 12 cm and the polygon is a square. why couldnt they just write 48?
As long as it says regular polygon the sides of the polygon will have equal sides.
ReplyDeleteIf you break up an inscribed regular polygon into triangles it will make isosceles triangles. The equilateral triangle thing only works for inscribed hexagons.
With the inscribed square, you can break the square up into two right triangles and use trig to solve for what you need.
oh okay. thanks :)
ReplyDeletelol found another question.
ReplyDeletea plate with a diameter of 24 cm is placed on a square mat,with no overhang. calculate the length of the diagonal of the mat.
so what i did was break it down into right triangles and figured out from there that one side was 12 cm and the other was 12 cm with the hypotenous being the unknown number. i used trig and got that the answer was the square root of 288. when i worked that out it went to 16.970 which i then multiplied by two to get the whole diagonal. when i checked in the back of the book though it said the answer was 24 square root 2. how did they get that?
If you take your answer and multiply it by 2 it should be the same as 24 square root 2.
ReplyDeletei dont understand how they got it in that format though.... how do i even read 24 square root 2? lol im pulling a blank sorry.
ReplyDeleteIf you break the square up into larger triangles you get sides of 24. Then if you solve for the hypotenuse and simplify the radical you will get the 24 root 2.
ReplyDeleteTo be honest if you don't get the answer the same as the back of the book just calculate their answer and check yours.